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MUS911
10-30-2006, 06:07 AM
is it Possible that:
1 = 2 ???

OK!!!

Let:
X = Y
Or
X - Y = 0 (equation 1)

Also:
2 ( X - Y ) = 0
Or
2 X - 2 Y = 0 (equation 2)

Since equation 1 + 2 are equal on

X - Y = 2 X - 2 Y
X - Y = 2 ( X - Y )

take out (X - Y) from both sides!

1 = 2

!!!!!!!
deth
10-30-2006, 06:16 AM
0/0 is undefined, that's why, right?
stmoritzer
10-30-2006, 06:42 AM
2*0 =0 or 3*0=0, anything multiplied with 0 is 0 , that's the "mistake" in above formula :wink:
stmoritzer
10-30-2006, 08:30 AM
LOL, again the multiplicaton with 0
but quite tricky to get :D
BADMIHAI
10-30-2006, 09:10 AM
Oh come on...this is pathetic. The only valid thing you can prove from the first equation is that a = b
Take

1=2

subtract 1 on both sides

1-1=2-1

0=1 not possible. Reduction ad absurdum.
5vz-fe
10-30-2006, 10:25 AM
a=b

(xa)

a^2=ab

(-b^2)

a^2-b^2=ab-b^2

(a+b)(a-b)=b(a-b)

a+b=b

... if a=b=1 then:

1+1=1

2=1

(a-b) is still 0 .... same problem
Mattk
10-30-2006, 08:41 PM
Yeah, you can't divide by 0. I was so happy when I worked it out the first time around a year ago whilst bored in maths, and then realised that it was just impossible. I'm sure you can use calculus to do fancy shit and get something like that.
TNT
10-30-2006, 09:07 PM
aaaaaahhhhhhhh math is crazy :crazyeyes:
5vz-fe
10-30-2006, 09:12 PM
http://img133.imageshack.us/img133/8696/findxgq7.jpg
http://img168.imageshack.us/img168/1204/2208467512bd2d90e76mbp8.jpg
http://img133.imageshack.us/img133/4296/220846757b3e1ea3de3mzp0.jpg
http://img168.imageshack.us/img168/9132/2208467615f1938fce9mpg0.jpg
http://yeskarthi.wordpress.com/2006/08/21/math-jokes/
r2r
10-30-2006, 09:20 PM
^^LOL^^
gigdy
10-31-2006, 12:32 AM
u + me = us
MUS911
10-31-2006, 03:32 PM
http://img133.imageshack.us/img133/8696/findxgq7.jpg
http://img168.imageshack.us/img168/1204/2208467512bd2d90e76mbp8.jpg
http://img133.imageshack.us/img133/4296/220846757b3e1ea3de3mzp0.jpg
http://img168.imageshack.us/img168/9132/2208467615f1938fce9mpg0.jpg
http://yeskarthi.wordpress.com/2006/08/21/math-jokes/


hahahaha,
nice one :wink:
gucom
10-31-2006, 04:37 PM
lololol

i got a similar "mathematical" equation from a friend of mine, its in dutch so i'll try to translate it...


(1)To get a woman, you need time and money => [Woman=time*money]
(2)We all know, time = money
(3)Therefore, applying (2) to (1) => [woman=money*money] => [woman=money˛]
(4)We also know money is the source of all problems => [money=√problems]
(5) If woman = money˛, that leads to: [woman=(√problems)˛]=>simplify:[woman=problems]
gigdy
10-31-2006, 04:56 PM
lololol

i got a similar "mathematical" equation from a friend of mine, its in dutch so i'll try to translate it...


(1)To get a woman, you need time and money => [Woman=time*money]
(2)We all know, time = money
(3)Therefore, applying (2) to (1) => [woman=money*money] => [woman=money˛]
(4)We also know money is the source of all problems => [money=√problems]
(5) If woman = money˛, that leads to: [woman=(√problems)˛]=>simplify:[woman=problems]

no problems should be evil. money is the root of all evil. also the assumption the the fact that u need time and money and this equals time*money is invalid.
gucom
10-31-2006, 05:00 PM
lol ofcourse its not a valid equation, its just a piece of fun :P it totally relies on the acceptance of those 3 assumptions, but thats not the point :wink:
TopGearNL
10-31-2006, 06:33 PM
You guys have to much time :mrgreen: